Y=0,08x^2-0,96x-5,12

Solution for Y=0,08x^2-0,96x-5,12 equation:

=0.08Y^2-0.96Y-5.12

We move all terms to the left:

-(0.08Y^2-0.96Y-5.12)=0

We get rid of parentheses

-0.08Y^2+0.96Y+5.12=0

a = -0.08; b = 0.96; c = +5.12;
Δ = b2-4ac
Δ = 0.962-4·(-0.08)·5.12
Δ = 2.56
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.96)-\sqrt{2.56}}{2*-0.08}=\frac{-0.96-\sqrt{2.56}}{-0.16}
$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.96)+\sqrt{2.56}}{2*-0.08}=\frac{-0.96+\sqrt{2.56}}{-0.16}
$